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LTD «PROFESSIONAL-V» today - it is 8 sales offices throughout the territory of Kazakhstan. To view the range of «PROFESSIONAL-V», you can in the following cities: Almaty, Astana, Pavlodar, Ust-Kamenogorsk, Atyrau, Aqtobe, Karaganda, Zhezkazgan. In each of these cities are located showrooms. Experienced managers are happy to tell you about products and provide expert help in selecting and ordering tools or equipment.

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According to market research tools and equipment, the price of products sold by the company, located in the middle and lower price ranges. Individual approach to customers - is also a common rule for our sales managers throughout the territory of Kazakhstan.

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How can I determine the necessary power of a generator?


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We propose a simple, practical way to determine the necessary power of a generator in five steps:

  1. Make a list of all the appliances (charges) and machines which will be connected to the generating set.
  2. Note down for every machine the power in Watt, the kind of charge (resistive / inductive) and the Power factor or cos phi.
  3. When cos phi = 1, then: 1 VA = 1 W.
    When cos phi < 1, then: VA = W / cos phi
    For electric motors (rule of thumb): take the power of the electric motor in HP and multiply it by 2.This is how we calculate the number of kVA the generator needs for starting the electric motor. The conversion of the HP's of the electric motor into the kVA's of the generator is a THUMB RULE which is correct in 90 % of the cases but NOT ALWAYS !!!
  4. Add all the obtained power in VA.
  5. Use a safety margin of ± 20% on the result of step 4.

When using this procedure to determine the necessary power of the generating set, you have to be sure that the power stated by the manufacturer of the generator is the real power, not the "commercial" power.

EXAMPLE: your need a generator for a 500 Watt heater, 5 strip lights of 50 Watt and a compressor of 2 HP.

  Watt Kind of charge Cos phi VA Saftey Margin kVA generator
Heater 500W Ohmic 1 500VA    
Tube light 5x50W Ind. 0,5 500VA    
Compressor 1500W Ind. 0,8 4000VA    
        5000VA x 1,2 = 6000VA
            = 6 kVA

 

What is the meaning of cos phi?
Cos phi
Power factor: with alternating current the absorbed (or apparent) power (kVA) of an inductive charge is larger than the active power (kW) really used by the charge. 

Cos phi= active power/apparent power.

Examples:
A. Resistive charges such as light bulbs and heating elements: cos phi = 1
B. Inductive charges:

Electric handtools cos phi ~ 0,97
Electric motor cos phi = 0,7 - 0,8
Strip light, welding transformer cos phi ~ 0,5

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